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2b^2-9b-12=0
a = 2; b = -9; c = -12;
Δ = b2-4ac
Δ = -92-4·2·(-12)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{177}}{2*2}=\frac{9-\sqrt{177}}{4} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{177}}{2*2}=\frac{9+\sqrt{177}}{4} $
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